Choose jour language!

---

|

The value of the term - the solution

#include <iostream>
#include<string>
using namespace std;

int main()
{
    string iz,s1,s2;
    getline( cin, iz );
  
    int poz[4];
//Returns the position of the computational operation or -1 if it is not found
    poz[0]=iz.find("+");
    poz[1]=iz.find("-");
    poz[2]=iz.find("*");
    poz[3]=iz.find("/");
    int i=0, p, q;
    while(poz[ i ]==-1){
        i++;
    }
    q=i;

    p=poz[i];
//numbers in the form of a string
    s1=iz.substr(0,p);
    s2=iz.substr(p+1);

//Convert numbers to int data
    int a=0, b=0;
    for(int i=0;i<s1.length();i++){
        char ch= s1.at(i);                          //character from the string at the i-th position, eg. ch = 3
        int c=ch-'0';                                     // c= '3' - '0', the difference of the codes of these digits is 3
        a=10*a+c;

    }
   
    for(int i=0;i<s2.length();i++){
        char ch= s2.at(i);
        int c=ch-'0';
        b=10*b+c;
    }
 
    switch(q){     //selection of the switch based on the value of the integer variable q, which represents
        case 0: cout<<a+b<<endl; break;            //calculation operation​
        case 1: cout<<a-b<<endl; break;
        case 2: cout<<a*b<<endl; break;
        case 3: cout<<a/b<<endl;
    }

    return 0;
}